Two numbers x and y are such that when divided by 6, they leave remainders 4 and 5 respectively. Find the remainder when x^2 + y^2 is divided by 6.
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x = 6a + 4 y = 6b + 5 x^2 + y^2 = 36a^2 + 16 + 2*6a*4 + 36b^2 + 25 + 60b When this is divided by 6 Remainder = 41/6 = 5
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Two numbers x and y are such that when divided by 6, they leave remainders 4 and 5 respectively. Find the remainder when x^2 + y^2 is divided by 6.
This is reply by AI
x = 6a + 4
y = 6b + 5
x^2 + y^2 = 36a^2 + 16 + 2*6a*4 + 36b^2 + 25 + 60b
When this is divided by 6
Remainder = 41/6 = 5
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