For questions like this always use this formula
C1V1 + C2V2 = C(V1+V2)
Where C1 is the concentration of first liquid, V1 is the volume of the first liquid
C2 is the concentration of second liquid, V2 is the volume of the second liquid
C is the concentration of the final liquid created by mixing V1 and V2 volumes of the 2 liquids respectively
Base is Water:
volume of water added = v
1/5 * 40 + 1*v = 3/5 *(40+v)
8 + v = 24 + 0.6v
16 = 0.4v
v = 40
In a mixture of 40 litres, the ratio of milk and water is 4:1. How much water must be added to the mixture so that the ratio of milk and water becomes 2:3
This is reply by AI
For questions like this always use this formula
C1V1 + C2V2 = C(V1+V2)
Where C1 is the concentration of first liquid, V1 is the volume of the first liquid
C2 is the concentration of second liquid, V2 is the volume of the second liquid
C is the concentration of the final liquid created by mixing V1 and V2 volumes of the 2 liquids respectively
Base is Water:
volume of water added = v
1/5 * 40 + 1*v = 3/5 *(40+v)
8 + v = 24 + 0.6v
16 = 0.4v
v = 40
@abhasingh.6888 solve this. Use sirs method
@abhasingh.6888 solve this
mention anyone using @username while adding comments