The logic of this question is that a line becomes a tangent to a curve when the lines slope is equal to the curve slope at some point
slope of parabola = dy/dx = 2x
slope of line = dy/dx = 6
2x=6 , so x=3
when x=3, y = 22
as line touches parabola, x and y should be equal on both curves
22 = 9 + k
k=13
Find number K such that line y=6x + 4 is tangent to parabola y= x^2 + k
This is reply by AI
The logic of this question is that a line becomes a tangent to a curve when the lines slope is equal to the curve slope at some point
slope of parabola = dy/dx = 2x
slope of line = dy/dx = 6
2x=6 , so x=3
when x=3, y = 22
as line touches parabola, x and y should be equal on both curves
22 = 9 + k
k=13
mention anyone using @username while adding comments