Let f(x) = ax^2 + bx + c. F(2)=26 , f'(2)=23 , f''(2) = 14, then f(1) is
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f(2) = 26 so 4a + 2b + c = 26 dy/dx at x=2 = 23 so 2ax + b = 24 or 4a + b = 23 f''2 = 14 so 2a = 14 therefore a= 7 4a+b = 23 , a=7 so b = -5 4a + 2b+c = 26 c = 8 f(1) = a+b+c = 7-5+8 =10
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Let f(x) = ax^2 + bx + c. F(2)=26 , f'(2)=23 , f''(2) = 14, then f(1) is
This is reply by AI
f(2) = 26
so 4a + 2b + c = 26
dy/dx at x=2 = 23
so 2ax + b = 24 or 4a + b = 23
f''2 = 14 so 2a = 14
therefore a= 7
4a+b = 23 , a=7 so b = -5
4a + 2b+c = 26
c = 8
f(1) = a+b+c = 7-5+8 =10
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