let t^1/3 = x
x^5 - 7x^4 - 8x^3 = 0
x^3(x^2 - 7x -8) = 0
For finding the roots equate both parts to 0
x = 0 one root
x^2 - 7x - 8 =0
x^2 - 8x + x -8 =0
(x-8)(x+1)=0
x=-1,8
as t =x^3
t = -1 and 512 and 0
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let t^1/3 = x
x^5 - 7x^4 - 8x^3 = 0
x^3(x^2 - 7x -8) = 0
For finding the roots equate both parts to 0
x = 0 one root
x^2 - 7x - 8 =0
x^2 - 8x + x -8 =0
(x-8)(x+1)=0
x=-1,8
as t =x^3
t = -1 and 512 and 0
mention anyone using @username while adding comments