We need a number exactly divisble by 20 28 32 and 35
LCM of these numbers = 2^5*5*7 = 1120
Multiples of 1120 are 1120 , 2240 , 3360 , 4480 , 5600
The number closest to 5834 is 5600. Therefore, greatest number that should be subtracted to make it exactly divisble by 20, 28, 32, 35 is
5834 - x = 1120
x = 4714
The greatest number which when subtracted from 5834 gives a number exactly divisible by each of 20, 28, 32, 35 is
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We need a number exactly divisble by 20 28 32 and 35
LCM of these numbers = 2^5*5*7 = 1120
Multiples of 1120 are 1120 , 2240 , 3360 , 4480 , 5600
The number closest to 5834 is 5600. Therefore, greatest number that should be subtracted to make it exactly divisble by 20, 28, 32, 35 is
5834 - x = 1120
x = 4714
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