A jar contains a mixture of 2 liquids A and B in the ratio 4:1. When 10 litres of the mixture is replaced with liquid B, the ratio becomes 2:3. The volume of liquid A present in the jar earlier was


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The key to solving such questions is to find one liquid and create an equation for it. For creating an equation use the below formula,
M1V1 + M2V2 = M(V1+V2)
Here,
M1 = Concentration % of liquid in first mixture
V1 = Volume of first mixture
M2 = Concentration % of liquid in second mixture
V2 = Volume of second mixture
M = concentration % of liquid after mixing

Let’s solve a question using this,
Taking B liquid as base,

First see which 2 liquids are getting mixed. We had a liquid with initial volume as V. This liquid’s (V-10) volume is getting mixed with pure 10l of B.

Concentration of B in liquid first jar = 4:1 so 1/5 or 0.2
Now, 10 l of this same liquid was replaced by 10 pure l of B
Concentration of B in the liquid that was added = 1 (Because the liquid added is pure B)
New concentration of B = 2:3 = 3/5 = 0.6

0.2 *(v-10) + 1*10 = 0.6* (v-10+10)
0.2v – 2 + 10 = 0.6v
8 = 0.4v
So, v = 20
This means initial volume was 20 l
So volume of A earlier was 20*4/5 = 16


@randominbox9 see this. Very good explanation


@randominbox9 i learned a lot from this article.


@randominbox9 Is there a link for more such articles?


mention anyone using @username while adding comments

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