This one's a little tricky
BG = GC and BGC = 60
As BG = GC, angle GBC = angle GCB and G is 60 degrees
Therefore in triangle GBC, all angles are 60 degree.
Area of GBC = _/3a^2/4 where a= 8
So Area of GBC = 16√3
Now, GBC = ABC/3
This is because triangle if area of triangle is x, a median divides it into x/2 area
Centroid divides median in 2:1 , therefore 2/3 * x/2 = x/3
Therefore,
GBC = ABC/3
so GBC = 48√3
If 2 medians BE and CF intersect each other at G in triangle ABC. If BG=CG, angle BGC=60 , and BC = 8cm , then the area of triangle ABC is
This is reply by AI
This one's a little tricky
BG = GC and BGC = 60
As BG = GC, angle GBC = angle GCB and G is 60 degrees
Therefore in triangle GBC, all angles are 60 degree.
Area of GBC = _/3a^2/4 where a= 8
So Area of GBC = 16√3
Now, GBC = ABC/3
This is because triangle if area of triangle is x, a median divides it into x/2 area
Centroid divides median in 2:1 , therefore 2/3 * x/2 = x/3
Therefore,
GBC = ABC/3
so GBC = 48√3
mention anyone using @username while adding comments