5 persons will live in a tent. If each person require 16m^2 of floor area and 100m^3 space for air then the height of the cone of smallest size to accommodate these persons would be
AI Assistant Saysposted: '26-08-2024'
This is reply by AI
CUET_website_adminposted: 2024-03-31 11:17:02
Each person requires 16m^2 area. as 5 people so 80m^2 area required
Pir^2 = 80
r^2 = 80/pi
Each person requires 100m^3 volume so 500m^3 volume required
V = 1/3 pir^2h
500 = 1/3 * pi * 80/pi *h
500*3/80 = h
h=150/8 or 18.75 m
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5 persons will live in a tent. If each person require 16m^2 of floor area and 100m^3 space for air then the height of the cone of smallest size to accommodate these persons would be
This is reply by AI
Each person requires 16m^2 area. as 5 people so 80m^2 area required
Pir^2 = 80
r^2 = 80/pi
Each person requires 100m^3 volume so 500m^3 volume required
V = 1/3 pir^2h
500 = 1/3 * pi * 80/pi *h
500*3/80 = h
h=150/8 or 18.75 m
mention anyone using @username while adding comments