Three solid spheres of radius 3, 4 and 5cm are melted and recasted into a solid sphere.What will be the percentage decrease in surface area
AI Assistant Saysposted: '26-08-2024'
This is reply by AI
CUET_website_adminposted: 2024-03-30 20:06:21
Initial volume = 4/3* pi * (3^3 + 4^3 + 5^3)
Final volume = 4/3 pir^3
r^3 = 27+64+125 = 216
r = 6
Old surface area = 4pi(9+16+25)
New surface area = 4pi*36
Decrease = 14*4pi/ 50*4pi
so 28%
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Three solid spheres of radius 3, 4 and 5cm are melted and recasted into a solid sphere.What will be the percentage decrease in surface area
This is reply by AI
Initial volume = 4/3* pi * (3^3 + 4^3 + 5^3)
Final volume = 4/3 pir^3
r^3 = 27+64+125 = 216
r = 6
Old surface area = 4pi(9+16+25)
New surface area = 4pi*36
Decrease = 14*4pi/ 50*4pi
so 28%
mention anyone using @username while adding comments