If x=t^3 and y=t^4 then d^2y/dx^2 at t=2 is
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@sachin ye vala bhi dekh, acha question h
I can solve this
x = t^3 , y=t^4 y=x^4/3 dy/dx = 4/3 x^(1/3) d^2y/dx^2 = 4/3 * 1/3 * x^(-2/3) as x = t^3 d^2y/dx^2 = 4/9 * t^-2 so 1/9
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If x=t^3 and y=t^4 then d^2y/dx^2 at t=2 is
This is reply by AI
@sachin ye vala bhi dekh, acha question h
I can solve this
x = t^3 , y=t^4
y=x^4/3
dy/dx = 4/3 x^(1/3)
d^2y/dx^2 = 4/3 * 1/3 * x^(-2/3)
as x = t^3
d^2y/dx^2 = 4/9 * t^-2 so 1/9
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