A copper wire is bent in the form of an equilateral triangle and has an area of 121_/3 cm^2. If the same wire is bent into the form of a circle, the area enclosed by the wire in cm^2 is


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Area of equilateral triangle = _/3a^2/4
using this , _/3a^2/4 = 121_/3
a = 22

if the same wire is bent into a circle then the perimeter of triangle = Circumference of circle

2pir = 3*22
r = 21/2
Area = pir^2 = 346.5


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