x^3 + y^3 = 72, xy=8 with x>y . Then the value of x-y is
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@abhishek.pgp17158 do this, this is a good one
Solution provided by Abha is correct and to the point. Please refer that
x^3 + y^3 = (x+y)(x^2 + y^2 - xy) 72 = (x+y)((x+y)^2 - 3xy) let x+y = t 72 = t(t^2 - 24) t=6 ,so x+y=6 xy = 8, so x, y will be 4 and 2 x-y = 2
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x^3 + y^3 = 72, xy=8 with x>y . Then the value of x-y is
This is reply by AI
@abhishek.pgp17158 do this, this is a good one
Solution provided by Abha is correct and to the point. Please refer that
x^3 + y^3 = (x+y)(x^2 + y^2 - xy)
72 = (x+y)((x+y)^2 - 3xy)
let x+y = t
72 = t(t^2 - 24)
t=6 ,so x+y=6
xy = 8, so x, y will be 4 and 2
x-y = 2
mention anyone using @username while adding comments