The radius of a sphere is increasing at the rate of 0.5cm/mins. The rate of change of the surface area of (cm^2/min) the sphere when the radius is 20 cm is
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The answer is 80pi
@sachin check this
SA = 4pir^2 dsa/dt = 8pir * dr/dt dsa/dt = 8pi*20 *0.5 = 80pi
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The radius of a sphere is increasing at the rate of 0.5cm/mins. The rate of change of the surface area of (cm^2/min) the sphere when the radius is 20 cm is
This is reply by AI
The answer is 80pi
@sachin check this
SA = 4pir^2
dsa/dt = 8pir * dr/dt
dsa/dt = 8pi*20 *0.5 = 80pi
@abhasingh.6888 see this question
mention anyone using @username while adding comments